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+3 votes
asked Jan 6 by Shivam Kumar Raj (160 points)

#include <stdio.h>

int main()
  int array[100], search, c, n;

  printf("Enter number of elements in array\n");
  scanf("%d", &n);

  printf("Enter %d integer(s)\n", n);

  for (= 0; c < n; c++)
    scanf("%d", &array[c]);

  printf("Enter a number to search\n");
  scanf("%d", &search);

for (= 0; c < n; c++)
    if (array[c] == search)    /* If required element is found */
      printf("%d is present at location %d.\n", search, c+1);
  if (== n)
    printf("%d isn't present in the array.\n", search);

  return 0;

1 Answer

0 votes
answered Jan 6 by Peter Minarik (45,000 points)
What is your question?

The program seems to work.

Of course, you can do a bit of optimization here, a bit of better user experience there, etc, but in principle, the logic seems right to me.
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