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Program that take 2 numbers from user print them their squares and sum of their squares

+1 vote
asked Apr 21, 2018 by Mehmood Ul Hassan (130 points)
Write a program that uses while loop to perform the following steps:

 a. Prompts user to input two integers Num1 and Num2. Num1 must be less than Num2. If not then Swap values of both numbers.

b. Output all numbers between Num1 and Num2.

c. Output Sum of all numbers between Num1 and Num2.

d. Output numbers and their squares between Num1 and Num2.

e. Output sum of squares of odd numbers between Num1 and Num2.

6 Answers

0 votes
answered Apr 23, 2018 by Kito Termilien (170 points)
what language?
0 votes
answered May 7, 2018 by anonymous
#include<stdio.h>

main()

{

int i,j;

printf("enter the numbers to print between them");

scanf("%d%d",&i,&j);

for(c=i;c<j;i++)

printf("%d", i);

sum+=i;

printf("%d",i*i);

}
commented May 14, 2018 by Ernest Nyambane (100 points)
it is not working
0 votes
answered May 11, 2018 by Archit Garg (220 points)
Answer of  a and b part

#include <iostream>

using namespace std;

int main()
{
    double num1,num2,temp,i;
    cin>>num1;
    cin>>num2;
    i=num1;
    if(num1>num2)
    {
        temp=num1;
        num1=num2;
        num2=temp;
    }
    while(i<num2)
    {
        if(i==num1)
        {}
        else
        cout<<i<<endl;
        i++;
    }
    return 0;
}
commented May 14, 2018 by Ernest Nyambane (100 points)
perfect one, it worked
0 votes
answered May 11, 2018 by Archit Garg (220 points)
Answer of C part

#include <iostream>

using namespace std;

int main()
{
    double num1,num2,temp,i,sum=0;
    cin>>num1;
    cin>>num2;
    i=num1;
    if(num1>num2)
    {
        temp=num1;
        num1=num2;
        num2=temp;
    }
    while(i<num2)
    {
        if(i==num1)
        {}
        else
        sum+=i;
        i++;
    }
    cout<<sum;
    return 0;
}
0 votes
answered May 11, 2018 by Archit Garg (220 points)
#include <iostream>

using namespace std;

int main()
{
    double num1,num2,temp,i;
    cin>>num1;
    cin>>num2;
    i=num1;
    if(num1>num2)
    {
        temp=num1;
        num1=num2;
        num2=temp;
    }
    while(i<num2)
    {
        if(i==num1)
        {}
        else
        cout<<i<<"    "<<i*i<<"   "<<endl;
        i++;
    }
    return 0;
}
0 votes
answered May 11, 2018 by anonymous
import math

num1 = int(input())

num2 = int(input())

if num1>num2:
    num1_ant = num1
    num1 = num2
    num2 = num1_ant
    

for numa in range(num1+1,num2):
    print(numa)
    print(math.sqrt(numa))
    
print(num1 + num2)

print(math.sqrt(num1) + math.sqrt(num2))
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