pointer in c

Question

Assuming all header files are included what is the output?

.......................................................................................................

void main()

{

int*p;

*p=1;

printf("%d",*p);

}

..................................................................

why the output of above lines is 1??????????????

Answer 1

Because *p address is assigns value of 1..so above lines output is 1..

Answer 2

void main()

{

 int var;

void *ptr=&var;

*ptr=5;

printf("%d\n%d\n",var,*ptr);

}

Answer 3

segmenation fault

Answer 4

its a simple programing logic, if u had not used pionters then also the output was comimg to be 1;

Answer 5

```c

int main(void)

{

    int a, *p;

    a = 1;

    *p = &a;

    printf("%d\n%d\n", a, p);

    return 0;

}

Answer 6

because estreek p has taken value 1

Answer 7

Because you take pointer variable as a integer as *P (which stores the data present in the address), and assign a value as  *P=1;

 so when you print the *P it gives the result as 1;

Answer 8

1

because here we are putting value to the pointer p by the statement  

   *p=1;