write a program to swap the alternate digits of the given number from right to left

Question

it should use only loops and decision making

Answer 1

main()

{

int no,rem,rev=0;

printf("enter a no");

scanf("%d",&no);

while(no!=0)

{

     no=no/10;

    rem=no%10;

   rev=rev*10+rem;

}

printf("%d is reverse no");

}

Answer 2

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#include <stdio.h>

unsigned int foo (unsigned int num);

int
main ()
{
  printf ("Hello World");

  printf ("\n reverse = %d", foo (556677));

  return 0;
}

unsigned int
foo (unsigned int num)
{
  unsigned int ret_num = 0, temp;

  while (num / 10 != 0)
    {
      ret_num += (num % 10);
      num /= 10;
      ret_num *= 10;

    }

  ret_num += num;

  return ret_num;
}

Comments

main()
{
int x,r,s=0;
printf("enter a number");
scanf("%d",&x):
while(x!=0)
{
x=x/10;
r=x%10;
s=s*10+r;
}
printf("%d",s);
}

Answer 3

#include <stdio.h>

#include <conio.h>

#include <string.h>

void main(){

    char str[20],tmp;

    int i,j;

    clrscr();

    printf("\nEnter a string : ");

    scanf("%s",str);

    printf("\n\nOriginal String     : %s",str);

    for(i=0;i<strlen(str);i=i+2){

    tmp = str[i];

    str[i] = str[i+1];

    str[i+1] = tmp;

    }

    printf("\nAfter Swap String      : %s",str);

    getch();

}