Input 3 numbers & output 1 if 3 numbers are diffrent & output 0 if numbers are repeated.

Question

You will be given 3 integers as input. The inputs may or may not be different from each
other. You have to output 1 if all three inputs are different from each other, and 0 if any
input is repeated more than once.
Input----- Three integers on three lines.
Output------ 1 if the three inputs are different from each other,
0 if some input is repeated more than once.

Answer 1

#include<stdio.h>

int main(){

int a,b,c;

scanf("%d %d %d",&a,&b,&c);

if(a==b||b==c||c==a)

printf("0");

else

printf("1");

return 0;

}

Answer 2

#include<stdio.h>

int main()

{

int a,b,c;

scanf("%d%d%d",&a,&b,&c);

if(a!=b&&a!=c&&b!=c)

printf("1");

else

printf("0");

return 0;

}

Answer 3

a,b,c=3,3,3

if (a==b==c): print(0)
elif(a in [b,c] or b in [a,c] or c in [a,b]): print(1)

Answer 4

num1=int(input("Enter 1st number : ")) #

num2=int(input("Enter 1st number : "))

num3=int(input("Enter 1st number : "))

if(num1==num2):

    print("0")

elif(num1==num3):

    print("0")

elif(num2==num3):

    print("0")

else:

    print("1")

Answer 5

#This code is in python version 3
a=int(input("Enter first number: "))
b=int(input("Enter second number: "))
c=int(input("Enter third number: "))
if a==b or b==c or a==c:
    print("0")
else:
    print("1")

Answer 6

#include <stdio.h>

int main()

{

int a,b,c;

scanf("%d%d%d",&a,&b,&c);

if(a!=b&&b!=c&&c!=a)

{

printf("1");

}

else

{

printf("0");

}

return(0);

}

Answer 7

#include <iostream>
#include<cmath>
using namespace std;
int main()
{
    int num1, num2, num3;
    cout<< "enter three numbers: ";
    cin>>num1;
    cin>>num2;
    cin>>num3,
    cout<<endl;
    if (num1 == num2 & num2 == num3)
        cout<<"one" <<endl;
    else
        cout<<"zero" <<endl;
       
    return 0;
}