Question

Write a program that asks the user to input a sentence and prints the number of letters and words in the sentence?

Answer 1

#include <stdio.h>

int main()
{
    int i=0,countl=0,countw=0;
    char my1[200],a;
    printf("enter sentence ");
  
   gets(my1);
    while(my1[i]!='\0')
    {
        countl++;
        if(my1[i]==' ')
        countw++;
         printf("%c ",my1[i]);
        i++;
       
    }
       printf("\n no of letter = %d",countl);
       countw++;
    printf("\n no of words = %d",countw);
    

    return 0;
}

Comments

There is a bug in this program, what if two contiguous spaces are there?

Answer 2

import java.util.Scanner;

public class demo {

    public static void main(String[] args) {

    Scanner input =new Scanner(System.in);
    int sum=0, len=0;
    System.out.println("please input the sequence");
    String str= input.nextLine();
    String[] st=str.split(" ");
    for(int i= 0;i<st.length;i++) {
      sum=sum+st[i].length();        
    }
    len=st.length;
    System.out.println("number of chars are:" + sum);
    System.out.println("number of words are:" + len);
    }

}

Answer 3

s=str(input('write a sentence : '))
sp=0
n=len(s)
for x in range(0,n):
    if (s[x])==" ":
        sp=sp+1
print('total words are : {0}'.format(sp+1))
print('total letters are : {0}'.format(n-sp))

Answer 4

#include<iostream>
#include<string>
using namespace std;
int main()
{
    string s;
    int i,x=0,y=0;
    getline(cin,s);
    int n=s.length();
    for(int i=0;i<n;i++)
    {
        if(s[i]!='/0') x++;
        if(s[i]==' ') y++;
    }
    cout<<x<<endl<<(y+1);
}