Question

how to get current year in C OnlineGDB

Answer 1

#include <stdio.h>
#include <time.h>
int main()
{
    time_t seconds=time(NULL);
    struct tm* current_time=localtime(&seconds); 
    
    printf("Current year = %d\n",(current_time->tm_year + 1900));
    return 0;
}

time(NULL) function returns the time since 00:00:00 UTC, January 1, 1970 (Unix timestamp) in seconds.

tm_year indicates the number of the current year starting from 1900. So, to print the actual value of the current year, you will have to add 1900 to its value.

You need to import time.h header file to use these features. 

Answer 2

#include <stdio.h>
#include <time.h>
int main()
{
    time_t seconds=time(NULL);
    struct tm* current_time=localtime(&seconds); 
    
    printf("Current year = %d\n",(current_time->tm_year + 1900));
    return 0;
}

Answer 3

A cool way is to use predefined macros in C. These include time, data, file etc encompassed between 2x underscores either side e.g. __TIME__

Below code prints only the year of current date:

#include <stdio.h>
int main()
{
    printf("%s", __DATE__ + 7); //usually prints 11 byte string, but this points to 8th byte to print year
    
    return 0;
}