python question

Question

i = input("What's the value of 2+3?\n")

if i == 5:
    print("Correct!")
    
else:
    print("Failed...")

why this code doesn't work correctly?

Answer 1

It should look like: i  = int(input("User input: "))

since you are asking for an integer, then 'user input' should be set as int. Your if statement is looking for a int value, not a string value, for just a quick fix you could do: if i == "5" as you can see I have strung the num value to a string value. This should now equal string to string.

Answer 2

i = input("What's the value of 2+3?\n")

if int (i) == 5:
    print("Correct!")
    
else:
    print("Failed...")
 

*the input function returns a string..and we cannot compare it an integer directly without converting it into an int.​

Answer 3

Because, a string '5' is stored in i not an int. So, its comparing int with str, which results in failure of this program.

Solution:

if int(i) == 5: