change this code to c++ with

Question

n,x = map(int,input().split()) lst = list(map(int,input().split())) su = 0 for i in range(n-1) :      z = lst[i] + lst[i+1]     if (z == x ) :          su = su + 1 print(su)

Answer 1

First of all, you should explain what your program does, as it is not clear...

Your program looks at a list of numbers (lst) and checks if any two neighbors add up to a certain value (x). 

Here's a similar program in C++:

#include <iostream>
#include <vector>

int main()
{
    std::cout << "The program asks for a sequence of integral numbers and checks if any two neighbours sum to a specific value." << std::endl;
    std::cout << "What sum should we look for? : ";
    int targetSum;
    if (!(std::cin >> targetSum))
    {
        std::cerr << "Not a number." << std::endl;
        return -1;
    }
    
    int number;
    std::vector<int> numbers;
    bool numberRead = true;
    std::cout << "Please, enter the next element in the sequence (not a number to finish)." << std::endl;
    do
    {
        std::cout << ": ";
        if (std::cin >> number)
            numbers.push_back(number);
        else
            numberRead = false;
    } while (numberRead);
    
    int matchCount = 0;
    int lastIndex = numbers.size() - 1;
    for (int i = 0; i < lastIndex; i++)
    {
        if (numbers[i] + numbers[i + 1] == targetSum)
            matchCount++;
    }
    
    std::cout << "Number of pairs summing up to " << targetSum << ": " << matchCount << std::endl;

    return 0;
}