can you write me a program for this plss

Question

First 2 terms will be constant 0 and 1 in Fibonacci series. Each new term in the Fibonacci sequence is generated by adding the previous two terms. Compute the Fibonacci series up to 15 numbers e.g. 1, 2, 3, 5, 8, 13, 21, 34, 55,89,….

Answer 1

#Program to compute first 15 numbers of the fibonacci series

#!/usr/bin/env/python3

def fibonacci(n):
    if n < 0:
        print("wrong input")
    elif n == 0:
        return 0
    elif n == 1:
        return 1
    else:
        return fibonacci(n - 1) + fibonacci(n - 2)

for i in range(0, 15):
    print(fibonacci(i))

Answer 2

#include<stdio.h>
int main(void)
{
    int x[100],n=15,i,j,a;
    for(i=0;i<n;i++)
    {
        for(j=0;j<3;j++)
        {
            if(j<=2)
              {
                  x[j]=j+1;

a=a+x[j];               
              }
              
                  x[i+2]=x[i]+x[i+1];

a=a+x[i];            
            
        }
    }
    printf("\nseries are:");
    for(i=0;i<n;i++)
    {
        printf("%d\t",x[i]);
    }

printf("\n sum of series no.:%d",a);   
    return 0;

Answer 3

Assuming Language required C it will not compute 15 no you can define how many no you want to compute for

#include<stdio.h>
void main()
{
int n,new,i;
int a[2]={0,1};
printf("Enter the no up to where you want to find the series\n");
scanf("%d",&n);

printf(" Fibonacci series\n0\n1\n");
for(i=3;i<=n;i++)
{
new=a[0]+a[1];
printf("%d\n",new);
a[0]=a[1];
a[1]=new;
}
}

Answer 4

#include<iostream>

using namespace std;

int main()

{

int n1=0,n2=1,n3,num,i;

cout<<"enter the number";

cin>>num;

cout<<n1<<" "<<n2<<" ";

for(i=1;i<=num;i++)

{

n3=n1+n2;

n1=n2;

n2=n3;

cout<<n3<<" ";

}

return 0;

}