How to make the number come in decimal. send the revised code correctly

Question

#include<stdio.h>

int main()
{
    int a,c;
    
    
    printf("\n Enter radius: ");
    scanf("%d",&a);
    c=3.14*a*a;
    printf("radius is %d",c);
}

Answer 1

• Decimal (floating point) numbers are stored as floats or doubles (double precision floating point numbers), not ints.
• It's good idea to name your variable with a meaningful name. What is a or c?
• Make sure you print the correct thing to the user and do not confuse him/her. (printf("radius is %d",c); says radius, but c is not the radius, rathe the area of the circle.)
• I'd recommend looking at the documentation of printf to understand how to format your output.

Here's the fixed code.

#include <stdio.h>

int main()
{
    float radius;
    printf("Enter radius: ");
    scanf("%f",&radius);
    float area = 3.14 * radius * radius;
    printf("The area is %f\n", area);
    return 0;
}

Answer 2

#include<stdio.h>

int main()
{
    Float a,c;  //put float or double
    
    
    printf("\n Enter radius: ");
    scanf("%d",&a);
    c=3.14*a*a;
    printf("radius is %d",c);
}

Answer 3

#include<stdio.h>

#include<conio.h>

int main()

{

int radius;

float area;

printf("enter the radius");

scan("%d",&radius);

area=3.14*radius*radius;

printf("the area is %.3f",area);

return 0:

}

Answer 4

use float intead of integer.

#include<stdio.h>

int main()
{
    float a,c;
    
    
    printf("\n Enter radius: ");
    scanf("%f",&a);
    c=3.14*a*a;
    printf("radius is %f",c);
}

Answer 5

#include<stdio.h>
#include<conio.h>
 int main()
 {
  float r=10,area, circum,PI=3.1214;
  area = PI * r * r;
  circum = 2* PI *  r;
  printf(" The area and the circumference of the circle are %f and %f respctively .",area,circum );
     
     
     return 0;
 }

Comments

If you post your solution, you should be in line with the original poster's goals. For instance, reading the radius from the user.

Also, getting the value of Pi wrong... (https://en.wikipedia.org/wiki/Pi)

You should pay more attention to the correctness of what you post, otherwise your post won't be helpful. :(