How to create a new list only with words that end with "ant" and have 7 caracters?

Question

This is the list that we start with:

liste_ant = ["enfant", "bonjour", "éléphant", "aidant", "saumon", "amusant", "blessant", "piscine", "broyant", "carburant", "devant", "vibrant"]

We have to create this new list:

new_list = [ "amusant", "broyant", "devant", "vibrant"]

Answer 1

Your similar question has been answered already. Now you just have to add one more check: how long is the string you're examining. Go online, do some research! ;) (Help: look for the function len())

Answer 2

liste_ant = ["enfant", "bonjour", "éléphant", "aidant", "saumon", "amusant", "blessant", "piscine", "broyant", "carburant", "devant", "vibrant"]
def filterant(val):
    if "ant" in val:
        if len(val) == 7:
            return val
        
def special(list1):
    return list(filter(filterant,list1))
    
print(special(liste_ant))

Comments

First of all, OP seems to be asking us to do their homework...

Second, your solution is for any 7 character length strings that contain "ant", not that end with "ant".