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I know the code is simple, but how do I make it work?

+5 votes
asked Jan 9 by Alexandr (250 points)
double mycos(double x,double eps)
{
    double s,an;
    int n;
    n=0;
    an=1;
    s=0;
    while(fabs(an)>eps)
    {
         s+=an;
         n++;
         an*=-x*x/(2.*n-1.0)/(2.0*n); 
    }
    return s;
}

1 Answer

+2 votes
answered Jan 9 by Peter Minarik (45,000 points)
selected Jan 10 by Alexandr
 
Best answer

What do you mean by "make it work"?

Using your function in the following scenario seems to work.

#include <stdio.h>
#include <math.h>

#define PI 3.1415926535897932384626433832795

double mycos(double x, double eps)
{
    double s = 0.0
    double an = 1.0;
    int n = 0;
    while (fabs(an) > eps)
    {
         s += an;
         n++;
         an *= - x * x / (2.0 * n - 1.0) / (2.0 * n); 
    }
    return s;
}

int main()
{
    printf("cos(60) = %lf\n", mycos(PI / 3, 0.1));
    return 0;
}

And the result is

cos(60) = 0.451689

It seems to be more or less correct (with a certain error level).

You can test it with various inputs and see where it makes mistakes (for instance instead of using PI / 3 radians, using 60 radians returns a wrong value). (Note: first I thought it calculates in degrees, hence I used 60 radians -- which I wrongly thought was 60 degrees and that's how I found this input to produce erroneous output.)

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