What should I put to return so that the program returns the array's numbers in order

Question

#include <iostream>

using namespace std;

int boi(int arr[], int size){
 cout<<"How many numbers are in your array?"<< endl;
 cin >> size;
 for(int x=0;x < size;x++){
    cout<<"Enter a number in your array"<< endl;
    cin >> arr[x];
    if(arr[x]>= arr[x+1]);
        arr[x] = arr[x+1];
        arr[x+1] = arr[x];
 }
}
    

int main(){
 int A[5];
 boi(A, sizeof A);
 return ;

}

I also tried this

#include <iostream>

using namespace std;

int boi(int arr[], int size){
 cout<<"How many numbers are in your array?"<< endl;
 cin >> size;
 for(int x=0;x < size;x++){
    cout<<"Enter a number in your array"<< endl;
    cin >> arr[x];
    if(arr[x]>= arr[x+1]);
        arr[x] = arr[x+1];
        arr[x+1] = arr[x];
 }
}
    

int main(){
 int A[5];
 boi(A, sizeof A);{
 cout << A[0-sizeof A] << endl ;
 }
}

Answer 1

Give the example for required output.

Answer 2

Hi, you're trying to do the bubble sort, so let's check this:

 for(int x=0;x < size;x++){
    cout<<"Enter a number in your array"<< endl;
    cin >> arr[x];
    if(arr[x]>= arr[x+1]);
        arr[x] = arr[x+1];
        arr[x+1] = arr[x];
 }

you are reading the pos "x" before read the pos "x+1", you need first read all the array,

by the way, the if doesn't need ";"

 for(int x=0;x < size;x++){
    cout<<"Enter a number in your array"<< endl;
    cin >> arr[x];
 }

for(int i=0;i<size;i++){

      if(arr[i]>arr[i+1]){

           aux=arr[i];

           arr[i]=arr[i+1];

           arr[i+1]=aux;         // You need an auxiliar to change two numbers, because                                                 // when you do arr[i]=arr[i+1], the information of arr[i] is lost

      }

}

and finally print the array

for(int i=0;i<size;i++){

            cout<<arr[i]<<" ";

}

Comments

thank you I was wondering that I was doing something wrong
 that would just make every element equal each other

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This is in C++ btw and they don't allow  aux... so is there another  keyword with the same purpose?

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Oh Im sorry,i forgot that, the aux is another int ( int aux;)
and this is my code if you want to see
#include <bits/stdc++.h>
using namespace std;
const int MaxN=1005;
int arr[MaxN];
int main(){
    int N,i,j,p,q;
    cin>>N;
    for(i=0;i<N;i++)cin>>arr[i];
    for(i=0;i<N;i++){
        for(j=0;j<N-1;j++){
            if(arr[j]>arr[j+1]){
                swap(arr[j],arr[j+1]);
            }
        }   
    }
    for(i=0;i<N;i++){
        cout<<arr[i]<<" ";
    }
}
by the way, the bubble sort is O(N^2) so we need to do 2 for's
https://en.wikipedia.org/wiki/Bubble_sort

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and sorry for my bad english, I speak spanish xD

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What is the point of const int [MaxN]
and declaring the arr?

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Usually the problem gives you the limits of the MaxN, and the limits for the bubble sort is 1000, because 1 second = 10^7 operations and 1000^2=10^6 operations, so that's why I declare the MaxN, the const is because i dont want to change it
and declare the array is for pre declare the memory