why its print all negitive number

Question

#include <stdio.h>

int main()
{
    int A[10],i;
    for(i=0;i<=9;i++){
         printf("enter the element");
         scanf("%d",&A[i]);
    }
    for(i=0;i<=9;i++){
         
       if(A[i]%2==0){
            printf("p%d ",A[i]);
           }
          else(A[i]%2==1);{
          
               printf("n%d",A[i]);}
          
    }
    
    return 0;
}

Answer 1

else(A[i]%2==1);{

the above line correctly:

else if (A[i] % 2 == 1) {

notice the if and no semicolon.

But to be fair, you could just write simply

else {

as at this point A[i] is already guaranteed to be odd. :)

One more note: the program does not print if a number is positive (p) or negative (n); it prints if a number is even (p) or odd (n). For this, it would be better to print "even" or "odd" and not "p" or "n".

If you need to decide if a number is positive or negative, then you should change your if condition accordingly.