Question

Susun program untuk menginput sebuah nilai integer lebih besar dari nol, yang di terima oleh variabel N bertipe long int, kemudian cetak jumlah digit nilai yang ada dalam N
contoh
Bila di input
5
12
724
141830322
maka tercetak
1
2
3
10

Answer 1

how is the last number 10 when it should be 9?

anyway here is a simple approach:

#include <iostream>
#include <math.h>

using namespace std;

int main()
{
    
    int x, y;
    cout << "Type in a number: ";
    cin >> x;
    
    
    if(x<10 && x > 0){
        y = 1;
    }
    if(x>=10) y = 2;
    if(x>=100) y =  3;
    if(x>=1000) y =  4;
    if(x>=10000) y =  5;
    if(x>=100000) y =  6;
    if(x>=1000000) y =  7;
    if(x>=10000000) y = 8;
    if(x>=100000000) y = 9;
    if(x>=1000000000) y = 10;
    
    
    cout << "Number of digits is: " << y;
    
    return 0;
}

Comments

I have no idea what the question's language is but this is a terrible way to count digits. Just create a loop that increments a counter while the test value > 0 and divide the number by 10 at the end of every iteration