this is my java code to return largest element from given array but it is showing indexoutofbound exception.please help

Question

import java.util.Arrays;

import java.util.Scanner;

public class LargestElement

{

public static void main(String[] args)

{

int f=0;

//fill your code here

int a1[]=new int[20];

for(int i=0;i<6;i++)

{

a1[i]=Integer.parseInt(args[i]);

}

f= checkLargestAmongCorner(a1);

System.out.println(f);

}

public static int checkLargestAmongCorner(int []a)

{

//fill your code here

int large=0;

int max=a[0];

if (a[1]>a[max]&&a[1]>a[Math.round(max/2)])

{

large = a[1];

}

else if(a[Math.round(max/2)]>a[1]&&a[Math.round(max/2)]>a[max])

{

large=a[Math.round(max/2)];

}

else if (a[max]>a[1]&&a[max]>a[Math.round(max/2)])

{

large=a[max];

}

return large;

}

}

Answer 1

The int variable "max" used in checkLargestAmongCorner represents the content of a[0], and does NOT represent the address of any element of a. Depending on the contents of a, this will definitely trigger an "index out of bounds" exception.

You should seriously read up on loops. Loops come into play when you want to process each element of an array. In this case, obviously you want to look at each element of the array to determine the largest element that the array contains.