I need the optimised code in c language of the given pattern below.

Question

3
44
555
6666
555
44
3

Answer 1

#include <stdio.h>

int main()
{
    int a,i;
     for(a=3;a<=6;a++)
    {
        for (i=1;i<=a-2;i++){
            printf("%d",a);
        }
        printf("\n");
    }
    for(a=5;a>=3;a--)
    {
        for (i=1;i<=a-2;i++){
            printf("%d",a);
        }
        printf("\n");
    }

    return 0;
}

Comments

Thanks a lot, jay for taking an interest in my problem.
Will you please make a change in my code to get the same output.

#include<stdio.h>
int main()
{
    int i,j,k=i,x=3;
    
    for(i=1;i<=7;i++){
        i<=4 ? k++ : k--;
        for(j=1;j<=4;j++){
            if(j<=k)
                printf("%d",x);
                else
                print(" ");
        }
            printf("\n");
    }
}

Answer 2

#include <stdio.h>

int main(void) {

    int i,j,k=3,t=5,g=3;

    for(i=0;i<4;i++)

    {

        for(j=0;j<=i;j++)

        {

            printf("%d",k);

        }

        printf("\n");

        k++;

    }

    for(i=0;i<3;i++)

    {

        for(j=0;j<g;j++)

        {

            printf("%d",t);

        }

        printf("\n");

        t--;

        g--;

    }

// your code goes here

return 0;

}

Comments

Thanks a lot, Bhanu Prakash for taking an interest in my problem.

Will you please make a change in my code to get the same output.

#include<stdio.h>
int main()
{
    int i,j,k=i,x=3;
    
    for(i=1;i<=7;i++){
        i<=4 ? k++ : k--;
        for(j=1;j<=4;j++){
            if(j<=k)
                printf("%d",x);
                else
                print(" ");
        }
            printf("\n");
    }
}