# plzz solve this

+1 vote

```         *
**
***
****
*****
******
*******
********
*********
**********```
`need to print a triangle like this`

answered Oct 2, 2018 by anonymous
#include <stdio.h>

void main()
{
int i,k,j;
for(i=10;i>0;i--)
{
for(k=i;k>0;k--)
{
printf(" ");
}

for(j=10;j>i;j--)
{
printf("*");
}
printf("\n");

}
}
answered Oct 2, 2018 by anonymous
#include <stdio.h>

int main()
{
int i,j;
for(i=0; i<=10; i++){
for(j=0; j<i; j++){
printf("*");
}
printf("\n");
}
}
–1 vote
answered Oct 2, 2018 by (120 points)
#include int main() { int m,n; for(m=0; m<11; m++){ for(n=0; n<m; n++){ printf("*"); } printf("\n"); } }
answered Oct 8, 2018 by Dinesh Koppula
#include<iostream>
using namespace std;
int main()
{
for (int i=10; i>=0; i--)
{
for(int j=0; j<=10; j++)
{
if (j>=i)
cout<<"*";
else
cout<<" ";
}
cout<<"\n";
}
return 0;
}
answered Oct 8, 2018 by anonymous
#include <stdio.h>

int main()
{
int i,j,k;
for(i=1;i<=10;i++)
{
for(j=i;j<10;j++)
{
printf(" ");
}
for(k=1;k<=i;k++)
{
printf("*");
}
printf("\n");
}
return 0;
}
answered Oct 9, 2018 by Bhavya
#include<stdio.h>

int main()

{

int i,j,n;

printf("enter no of rows");

scanf("%d",&n);

for(i=0;i<n;i++)

{

for(j=0;j<n;j++)

{

if(i+j>=9)

{

printf("*");

}

else

{

printf(" ");

}

}

printf("\n");

}

}
answered Oct 9, 2018 by (420 points)

simple C Code:

#include <stdio.h>

void printStar(int n); //helper function

int main()
{
int NUM;

printf("Enter num of lines: ");
scanf("%d",&NUM);

for(int i =0 ; i<=NUM;i++)
{
printStar(i);
printf("\n");
}

return 0;
}

void printStar(int n)
{
for(int i=0;i<n;i++)
printf("*");
}

answered Oct 10, 2018 by anonymous
Nice, how everybody is doing his/her homework. You didn't helped him/her at all
answered Oct 10, 2018 by (150 points)
#include <stdio.h>

int main()
{
int i,j;

for(i=0;i<=9;i++)
{
for(j=0;j<=9;j++)
{
if(i<9-j)

{
printf(" ");
}

else
printf("*");

}
printf("\n");
}

return 0;
}
answered Oct 10, 2018 by anonymous
#include stdio.h>

int main()

{

int r,n,s,c;

printf("enter no.of rows:");

scanf("%d",&n);

s=n;

for(r=1;r<=n;r++)

{

for(c=1;c<s:c++)

printf(" ");

s--;

for(c=1;c<=r;c++)

printf("  *");

printf("\n");

}

return 0;

}