can I get explanation of this program????

Question

#include<stdio.h>
#include<conio.h>
int main()
{
    int n=1;
    printf("%d%d%d",n++,n,++n);
    return 0;
}

Answer 1

#include<stdio.h>

int main()
{
    int n = 1;
    // printf("%d%d%d",n++,n,++n);
    // replaced above with three descriptive prints and new lines "\n" (not to be confuse with variable n)
    // %d is a place holder for the decimal format of n to be printed. Three %d in the original for three values of n

    printf("\nprint n as is and then increment it: n = %d", n++);
    printf("\nprint n after incremented by previous printf: n = %d", n);
    printf("\nincrement n and then print it: n = %d", ++n);
    
    return 0;
}