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write a programme to generate the following pattern
0
votes
asked
Jun 1, 2019
by
anonymous
closed
Jun 7, 2019
by
Admin
123456
12345
1234
123
12
1
closed with the note:
Closing question since already solved.
7 Answers
0
votes
answered
Jun 1, 2019
by
anonymous
#include <stdio.h>
int main()
{
int i,j,k=1;
for(i=1;i<=6;i++)
{
for(j=6;j>=i;j--)
{
printf("%d",k);
k++;
}
k=1;
printf("\n");
}
}
commented
Jun 5, 2019
by
Archana Shah
#include <stdio.h>
int main()
{
int i,j,k=1;
for(i=6;i>=1;i--)
{
for(j=1;j<=i;j++)
{
printf("%d",j);
}
printf("\n");
}
}
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0
votes
answered
Jun 2, 2019
by
Jack sparrow
(
220
points)
#include<stdio.h>
int main()
{
int a,i,j,c=1;
scanf("%d",&a);
for(i=a;i>=1;i--)
{
for(j=1;j<=a;j--)
printf("%d",c++);
printf("\n");
}
return 0;
}
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0
votes
answered
Jun 3, 2019
by
anonymous
#include <stdio.h>
int main()
{
int l,m,n=1;
for (l=0;l<6;l++)
{
for (m=0;m<6;--m)
{
printf("%d",n);
n++;
}
n=1;
printf("\n");
}
}
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0
votes
answered
Jun 3, 2019
by
anonymous
public class Main
{
static int k=0;
public static void main(String[] args) {
for(int i=1;i<=6;i++){
for(int j = 6;j>=i;--j){
k++;
System.out.print(k);
}
k=0;
System.out.print("\n");
}
}
}
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0
votes
answered
Jun 3, 2019
by
Jack sparrow
(
220
points)
#include<stdio.h>
int main()
{
int a,i,j,c=1;
for(i=1;i<=a;i++)
{
for(j=1;j<=a;j--)
{
printf("%d",c++)
}
c=1
printf("\n");
}
return 0;
}
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0
votes
answered
Jun 4, 2019
by
AZHARUDEEN S
(
140
points)
#include<stdio.h>
int main()
{
int num,i,j,sp,a=1;
scanf("%d",&num);
for(i=1;i<=num;i++)
{
for(sp=1;sp<row;sp--)
{
printf(" ");
}
for(j=1;j<=num;j++)
{
printf("%d,a);
return 0;
}
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0
votes
answered
Jun 4, 2019
by
vishnu
#include<stdio.h>
int main()
{
int input,col,line,value;
scanf("%d",&input):
for(line=1;line<=input;line++)
{
value=1;
for(col=line;col<=ip;col++)
{
printf("%d",value);
value++;
}
printf("\n");
}
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