what is the logic of this program

Question

#include <stdio.h>
    void main()
    {
        int x = 0, y = 2, z = 3;
        int a = x & y |z;
        printf("%d", a);
    }

Answer 1

& and | are bit wise operators then operation will be performed as bit by bit
        given  x = 0, y = 2, z = 3;
          x & y |z means 000 & 010 | 011 
       

Answer 2

There is nothing in the logic You are getting values by operating of some bitwise operators. your initializing the integer values in the declaration part itself. So You are getting Direct Answer

Answer 3

Answer is 3.that a will perform that condition.so,answer is 3

Answer 4

0&2|3

0&2

false & 2 =false=0

0|3

false | 3 =true =3

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Guide/Expressions_and_Operators

Answer 5

first bitwise and will operate so for x & y as x=0 it is "false". so answer for x & y is false .now for "or" operator first one is false it will check for next,that is z=3 which is true.3 is assigned to a Now a=3 so output is 3.