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write the logic to count repeated even elements

–1 vote
asked Aug 28, 2019 by guru

1 Answer

0 votes
answered Sep 13, 2019 by Jongbo (460 points)
#include <stdio.h>

void main()
    int count=0;
    int i;
    int nums[10];
            int sNum = nums[i];
            for(int j=i;j>0;j--){
                    count = count+1;

sorry this isnt fully right. I wanted to fix it but I had to go, but this might give you hint, so if you can manipulate it, it will help you
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