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difference between two expression given below
+4
votes
asked
Sep 3, 2019
by
operator
assume x=5,y=5;
x*=3+5;
y=y*3+5;
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9 Answers
+3
votes
answered
Sep 3, 2019
by
anonymous
x*=3+5 will become x=x*(3+5) which will be x*8 = 40
where y=y*3+5 will be solved by BODMAS = 20
commented
Sep 11, 2019
by
ROSHINI18
(
110
points)
distint and clear
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0
votes
answered
Sep 3, 2019
by
remember me
for first expression is short end it can also written as x=x*(3+5)
for second it is multiplication of var y with 3 and then adding it to 5
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+1
vote
answered
Sep 3, 2019
by
anonymous
Using order of Operator Precedence
x*=3+5 //x=5*(3+5)
y=y*3+5 //y=y*3+5
Answers = 40, 20
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0
votes
answered
Sep 10, 2019
by
Shubham Pal
(
140
points)
both are same
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0
votes
answered
Sep 11, 2019
by
anonymous
first one is x= x*(3+8);//x*=3+5 *= is compound operator
second one is y = y*3+5
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0
votes
answered
Sep 12, 2019
by
Prakash Hadgal
(
180
points)
x*=3+5; ==> x = x*(3+5) ==> 40
y=y*3+5; ==> y = (y*3)+5 ==> 20
Now you can see the exact difference.
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+1
vote
answered
Sep 18, 2019
by
anonymous
*= is a compound operator
+, * , - , / are operators
x *= 3 + 5 can be written as x = x * (3 + 5).Here we need to consider BODMAS rule. So, output is 40
y = y * 3 + 5 ==> output is 20
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0
votes
answered
Sep 18, 2019
by
vikash22kumar
(
200
points)
x*=(3+5) x=x*(8) x=40
y=y*3+5 y=15+5 y=20
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0
votes
answered
Sep 27, 2019
by
anonymous
your first expression will be compiled as x=x*(3+5)
and your second one as y=(y*3)+5
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