2d array chess example

0 votes
asked Sep 4, 2019 by basel 1 flag
how to make the able moves for queen in chess by java

1 Answer

–1 vote
answered Dec 26, 2019 by anonymous
import java.io.*;

import java.util.*;

public class Chess

{

public static void main (String[] args)

{

Scanner sc=new Scanner(System.in);

int n = 4;

int k = 0;

int x = 2;

int y = 2;

int obstPosx[] = { 4,3 };

int obstPosy[] = { 2,3 };

int d11, d12, d21, d22, r1, r2, c1, c2;

d11 = Math.min( x-1, y-1 );

d12 = Math.min( n-x, n-y );

d21 = Math.min( n-x, y-1 );

d22 = Math.min( x-1, n-y );

r1 = y-1;

r2 = n-y;

c1 = x-1;

c2 = n-x;

for (int i = 0; i < k; i++)

{

if ( x > obstPosx[i] && y > obstPosy[i] && x-obstPosx[i] == y-obstPosy[i] )

{

d11 = Math.min(d11, x-obstPosx[i]-1);

}

if ( obstPosx[i] > x && obstPosy[i] > y && obstPosx[i]-x == obstPosy[i]-y )

{

d12 = Math.min( d12, obstPosx[i]-x-1);

}

if ( obstPosx[i] > x && y > obstPosy[i] && obstPosx[i]-x == y-obstPosy[i] )

{

d21 = Math.min(d21, obstPosx[i]-x-1);

}

if ( x > obstPosx[i] && obstPosy[i] > y && x-obstPosx[i] == obstPosy[i]-y )

{

d22 = Math.min(d22, x-obstPosx[i]-1);

}

if ( x == obstPosx[i] && obstPosy[i] < y )

{

r1 = Math.min(r1, y-obstPosy[i]-1);

}

if ( x == obstPosx[i] && obstPosy[i] > y )

{

r2 = Math.min(r2, obstPosy[i]-y-1);

}

if ( y == obstPosy[i] && obstPosx[i] < x )

{

c1 = Math.min(c1, x-obstPosx[i]-1);

}

if ( y == obstPosy[i] && obstPosx[i] > x )

{

c2 = Math.min(c2, obstPosx[i]-x-1);

}

}

System.out.println(d11 + d12 + d21 + d22 + r1 + r2 + c1 + c2);

}

}
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