Question

Como hacer un programa con un bucle infinito que muestre los tres primeros divisores de un número?

Answer 1

What if the number is 2? Then there is only one divisor.  How do you display 3 divisors?

Also, why do you need an infinite loop since numbers are not infinitely large?  You only need a loop from 1 to n/2.

You could write it like this (this one displays all the divisors - not just three...):

https://onlinegdb.com/YJPVoIzyW3

#include <stdio.h>
#include <stdlib.h>

int main(int argc,char *argv[]) {
    if (argc==1) return 1;
    int n=atoi(argv[1]);
    for (int i=1;i<=n/2;i++)
        if (!(n%i))
            printf("%d\n",i);
    return 0;
}