Question

Can anyone tell me to execute the code of y = ++ x when x = 3, please tell me all how to write it if you can

Answer 1

while(x==3)

y=++x;

According to your question this is the solution. Otherwise kindly explain your question further more

Answer 2

#include<stdio.h>

int main()
{
    int a, b;
    a = 5;
  b = ++a;
  
    printf ("data after pre-increment is  %d ",b);
}

Answer 3

I'm guessing you are looking for this

if(x==3)
{
     y = ++x;
}

Answer 4

#include <stdio.h>

int main()
{
   int x,y;
   x=3;
   y=++x;
   return 0;
}

output:

Answer 5

#include <stdio.h>
#include <stdlib.h>

int main()
{
   int x,y;
   x=3;
   y=++x;
   return 0;
}

output:

Comments

#include <stdio.h>
#include <stdlib.h>

int main()
{
   int x, y;
   x = 3;
   printf("this is x %d ", x);
   y = ++x;
   printf("this is y %d ", y);
   printf("this is y %d ++x %d ", y, x);
   
   // keep in mind ++ can be before or after, the variable
 // it will determine when the calculations take place
   return 0;
}