Start by creating a dynamic array of size 5. Whenever the user enters too many numbers, grow the size of the array by 2

Question

when the 6^th number is entered:

Create a new dynamic array of size 10

Transfer the existing 5 numbers

Delete the old array

Answer 1

#include<stdio.h>
#include<stdlib.h>
#include<string.h>
int main() {
  int *first = (int*) malloc(sizeof(int)*5);
  int *last ;
  int count=0,fact=5;
  while(1){
      scanf("%d",&first[count]);
      if((count+1)==fact){
          last = (int*) malloc(sizeof(int)*fact);
          memcpy(last,first,sizeof(int)*fact);
          fact*=2;
          free(first);
          first = (int*) malloc(sizeof(int)*fact);
          memcpy(first,last,sizeof(int)*fact);
          free(last);
      }
  }
}

Answer 2

#include<stdio.h>

#include<stdlib.h>

#include<string.h>

int main() {

int *first = (int*) malloc(sizeof(int)*5);

int *last ;

int count=0,fact=5;

while(1){

scanf("%d",&first[count++]);

if((count+1)==fact){

last = (int*) malloc(sizeof(int)*fact);

memcpy(last,first,sizeof(int)*fact);

fact*=2;

free(first);

first = (int*) malloc(sizeof(int)*fact);

memcpy(first,last,sizeof(int)*fact);

free(last);

}

}

}