Question

Write a program that takes 4 numbers from the user and finds how many are odd

Answer 1

num = int(input(Enter num))

if num%2 != 0 :

      print("Odd no")

Answer 2

#include <stdio.h>

int main()
{
    int odd=0,aux;
    for(int i=0;i<4;i++){
    printf("%d°",i);
    /*printf("%d%c",i,248);//Windows*/
    scanf("%d",&aux);
    if(aux%2)
    odd++;
    }
    printf("%d",odd);
    return 0;
}

Answer 3

#include <stdio.h>

int main()
{
    int odd=0,aux;
    for(int i=0;i<4;i++){
    printf("%d°",i);
    /*printf("%d%c",i,248);//Windows*/
    scanf("%d",&aux);
    if(aux%2)
    odd++;
    }
    printf("%d",odd);
    return 0;
}

Answer 4

#include <stdio.h>
int main()
{
int i,n,odd,a[10];
odd=0;
printf("enter n value");
scanf("%d",&n);
for(int i=0;i<n;i++)
{
    scanf("%d",&a[i]);
}
for(i=0;i<n;i++)
{
if(a[i]%2!=0)
odd++;
}
printf("%d",odd);
    return 0;
}

Answer 5

#include <iostream>

using namespace std;

int main()
{
    int a[4],odds = 0;
    cout<<"Enter numbers"<<endl;
    for(int i =0;i<4;i++)
    {
    std::cin >> a[i] ;
    if(a[i]%2 != 0)
    {
        odds++;
    }
    
    }
    cout<<"\n";
    cout<< "Odd numbers : " << odds ;
    return 0;
}

Answer 6

a = [0,0,0,0]
evennum = 0
oddnum = 0
for i in range(4):
    a[i] = int(input("Enter number "+str(i+1)+": "))
    if a[i]%2 == 0:
        evennum = evennum + 1
    else:
        oddnum = oddnum + 1
print("No. of even numbers = "+ str(evennum))
print("No. of odd numbers = "+ str(oddnum))

Answer 7

//c program to find if the entered 4 numbers are odd or even

#include <stdio.h>

int main()
{
    int a[4],i;
    printf("Enter 4 numbers:");
    for(i=0;i<4;++i)
    {
        scanf("%d",&a[i]);
    }
    for(i=0;i<4;++i)
    {
        if(a[i]%2==0)
        printf("%d is even\n",a[i]);
        else
        printf("%d is odd\n",a[i]);
    }

    return 0;
}

Answer 8

num = int(input("Enter num"))
if num%2 != 0 :
    print("Odd no")
else:
    print("Even no")