How do you make a code that counts up by 2s?

0 votes
asked Nov 14, 2017 by anonymous

3 Answers

0 votes
answered Feb 7, 2018 by anonymous

dhhanpal singh

0 votes
answered Feb 9, 2018 by Jake Swink (140 points)
Depending on the langauge that you are writing in... but here is some psedu-code

For (int num; add 2; while num is >0)

return num;
0 votes
answered Feb 14, 2018 by Attila

// For C language

#include <stdio.h>

int main()
{
    int i=0, a=0, t[20];        //use _t[20]_ for example if you need 20 element
    while(i<20)                 //use _i<20_ for example if you need 20 element
    {
        if(!(a%2))              //here you can set the "by 2s" part, _if(!(a%3))_ is for "by 3" etc. [you can write _if((a%2)==0)_ instead of _if(!(a%2))_ aswell]
        {
        t[i]=a;                 //here you load into the t[] array on (i)th index the actual value (a) that is OK for your criterion (above if part); now t[0]=0 t[1]=2 t[2]=4 etc.
        printf("%d\n",t[i]);    //not needed, just for checking in terminal
        i++;                    //here you increment the (i) index, this cause t[0] t[1] t[2] etc (not overloading into one index every value, just step it forward in the array)
        }
    a++;                        //here you increment the value to get bigger and bigger numbers
    }

    return 0;
}

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