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find the sum of all numbers upto n
+1
vote
asked
Apr 2, 2020
by
NAVYA SRI MUTHINENI
(
140
points)
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8 Answers
0
votes
answered
Apr 4, 2020
by
Bilal
(
170
points)
#include<stdio.h>
int main (){
int i,n,sum=0;
printf("Please enter a number:");
scanf("%d",&n);
for(i=1;i<=n;i++){
sum=sum+i;
}
printf("Sum of all number to n is : %d",sum);
return 0;
}
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0
votes
answered
Apr 4, 2020
by
Prabhat Nayak
(
220
points)
//i am doing by using c language
#include<stdio.h>
void main()
{
int i,n,sum;
printf("enter value of n");
scanf("%d",&n);
for(i=1;i<=n;i++)
{
sum+=i;
}
printf("sum is %d",sum);
}
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0
votes
answered
Apr 4, 2020
by
pjvendhan
(
140
points)
n=int(input("enter the last number ypu want:"))
sum=0
for i in range(0,n):
sum+=i
print(sum)
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+1
vote
answered
Apr 5, 2020
by
Luigi Rodorigo
(
280
points)
uint32_t sum(uint32_t n) { return n*(n+1)/2; // thank you gauss! }
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0
votes
answered
Apr 5, 2020
by
Frenst
(
140
points)
// same result without loop for
#include <stdio.h>
int main()
{
int i,n,sum=0,sum1=0;
printf("Please enter a number:");
scanf("%d",&n);
sum=(n+1)*n/2;
printf("Sum of all number to n is : %d",sum);
return 0;
}
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0
votes
answered
Apr 5, 2020
by
Manav Changela
(
190
points)
I used a simple formula from Arithmetic Progression
#include<stdio.h>
void main()
{
int n,sum;
printf("ENTER VALUE OF n:");
scanf("%d",&n);
sum=0.5*n*(1+n);
printf("\n sum=%d",sum);
}
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0
votes
answered
Apr 6, 2020
by
1916114
(
260
points)
#include <stdio.h>
int main
{
int a,i,c=0;
printf("ENTER THE NUMBER");
scanf("%d",&a0;
for(i=0;i<=a;i++)
c=c+i;
printf("the required sum%d",c);
return 0;
}
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0
votes
answered
Apr 6, 2020
by
Anmol Jain
(
150
points)
#include<stdio.h>
void main()
{
int i,n ,sum=0;
printf("Enter the number:");
scanf("%d",&n);
for(i=0;i<=n;i++)
{
sum=sum+i;
}
printf("The sum of numbers upto 'n' is %d",sum);
}
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