Need help with a C programming Homework

Question

Simply encrypt a string, add 1 to the ASCII code of each character, and then print out the encrypted string.

Answer 1

#include <string.h>

#include <stdio.h>

int main() {

      char str[] = "some string";

      for (int i = 0; i < strlen(str); i++) {

             str[i] = (int)str[i] + 1;

       }

      printf("%s", str);

      return 0;

}

Answer 2

I tried this but and it failed but here's my code in c++

#include <stdio.h>
#include <iostream>
#include <math.h>
#include <stdlib.h>
#include <string>
using namespace std;

char chpeir[52]={'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z','1','2','3','4','5','6','7','8','9','!','@','#','$','%','^','&','*','(',')','-','_','=','+','[',']','{','}'};
char text[500];
char chpier_text[500];
int main()
{
    cin>>text;
        for(int letter = 0;letter<500;letter++)
    {
           for(int letter_find=0;letter_find<52;letter_find++)
        {
                if(chpeir[letter_find]==text[letter])
            {
                chpier_text[letter]=chpeir[((letter_find+26)%52)];
                break;
            }
           
        }
       
    }
    cout<<chpier_text;
}