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Someone help with my bit division problems please

0 votes
asked Jan 30, 2018 by Lee Shallis (340 points)
edited Jan 30, 2018 by Lee Shallis

I tried everything I could think of and still can’t get it to work, here's the code:


zuv_t* __zuvDiv( zuv_t *num, zuv_t const *val, zuv_t *rem ) {
    if ( !_zuvRlNum(num) || !_zuvRlNum(rem) ||
        num->size != rem->size || num->bits > (USHRT_MAX * CHAR_BIT) )
        return NULL;
    memcpy( rem->buff, num->buff, num->size );
    memset( num->buff, 0, num->size );
    if ( !_zuvRlNum(val) ) {
        memset( rem->buff, 0, rem->size );
        return num;
    }
    if ( _zuvLth( rem, val ) )
        return num;
    _zbit_t n = _zuvBwCmp( rem, 0 ), nbeg = _CalcZbit( num->zero );
    zuv_t sec = *rem;
    sec.bits = 1;
    sec.zero = n.num;
    while ( sec.bits < num->bits && _zuvMeq( rem, val ) ) {
        _DecZbit( n, nbeg, break )
        if ( _zuvMeq( &sec, val ) ) {
            _zuvSub( &sec, val );
            num->buff[n.pos] |= n.bit;
        }
        sec.zero--;
        sec.bits++;
        n.bit >>= 1;
    }
    return num;
}

And here's the results:


2310 one = 00000111010110111100110100010101u, 123456789u
2311 two = 00000000000000000000000001110000u, 7u
2312 (val1 /= val2) = 00000001000011010001110101001100u
2313 (num1 /= num2) = 00000001000111111111111111111111u
2320 one = 00000111010110111100110100010101u, 123456789u
2321 two = 00000000000000000000000011010000u, 13u
2322 (val1 /= val3) = 00000000100100001110100001100100u
2323 (num1 /= num3) = 00000000100100011111111111111111u
2330 one = 00000000000000000000000000000111u, 7u
2331 two = 00000000000000000000000011010000u, 13u
2332 (val2 /= val3) = 00000000000000000000000000000000u
2333 (num2 /= num3) = 00000000000000000000000000000000u

Edit: Formatting had been broken so changed it (the formatting) to something easier to read

Edit 2: Found I had been referencing num in places I should have been referencing rem, corrected that and updated above code & results

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