# Someone help with my bit division problems please

edited Jan 30, 2018

I tried everything I could think of and still can’t get it to work, here's the code:

```zuv_t* __zuvDiv( zuv_t *num, zuv_t const *val, zuv_t *rem ) {
if ( !_zuvRlNum(num) || !_zuvRlNum(rem) ||
num->size != rem->size || num->bits > (USHRT_MAX * CHAR_BIT) )
return NULL;
memcpy( rem->buff, num->buff, num->size );
memset( num->buff, 0, num->size );
if ( !_zuvRlNum(val) ) {
memset( rem->buff, 0, rem->size );
return num;
}
if ( _zuvLth( rem, val ) )
return num;
_zbit_t n = _zuvBwCmp( rem, 0 ), nbeg = _CalcZbit( num->zero );
zuv_t sec = *rem;
sec.bits = 1;
sec.zero = n.num;
while ( sec.bits < num->bits && _zuvMeq( rem, val ) ) {
_DecZbit( n, nbeg, break )
if ( _zuvMeq( &sec, val ) ) {
_zuvSub( &sec, val );
num->buff[n.pos] |= n.bit;
}
sec.zero--;
sec.bits++;
n.bit >>= 1;
}
return num;
}
```

And here's the results:

```2310 one = 00000111010110111100110100010101u, 123456789u
2311 two = 00000000000000000000000001110000u, 7u
2312 (val1 /= val2) = 00000001000011010001110101001100u
2313 (num1 /= num2) = 00000001000111111111111111111111u
2320 one = 00000111010110111100110100010101u, 123456789u
2321 two = 00000000000000000000000011010000u, 13u
2322 (val1 /= val3) = 00000000100100001110100001100100u
2323 (num1 /= num3) = 00000000100100011111111111111111u
2330 one = 00000000000000000000000000000111u, 7u
2331 two = 00000000000000000000000011010000u, 13u
2332 (val2 /= val3) = 00000000000000000000000000000000u
2333 (num2 /= num3) = 00000000000000000000000000000000u```

Edit: Formatting had been broken so changed it (the formatting) to something easier to read

Edit 2: Found I had been referencing num in places I should have been referencing rem, corrected that and updated above code & results