what is wrong with my code for bubble sort

Question

#include<stdio.h>

#include<conio.h>

#include<stdlib.h>

void

main ()

{

  int i, j, n, temp;

  int a[20];

  printf ("Enter the size of array\n");

  scanf ("%d", &n);

  printf ("Enter the elements of an array\n");

  for (i = 0; i < n; i++)

    {

      scanf ("%d", &a[i]);

    }

  printf (" the elements of an array before sorting are:\n");

  for (i = 0; i < n; i++)

    {

      scanf ("%d\t", &a[i]);

    }

  for (i = 0; i <= n - 1; i++)

    {

      for (j = 0; j < n - 1; j++)

{

  if (a[j] > a[j + 1])

    {

      temp = a[j];

      a[j] = a[j + 1];

      a[j + 1] = temp;

    }

}

    }

  printf ("the elements of an array after sorting are:\n");

  for (i = 0; i < n; i++)

    {

      scanf ("%d", &a[i]);

    }

}

Answer 1

Line 19

In the second for loop use printf instead of scanf

Comments

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Answer 2

When you're about to print the numbers, you're supposed to use printf(), not scanf(). Otherwise, things should work fine.

Answer 3

#include<stdio.h>

#include<conio.h>

#include<stdlib.h>

void

main ()

{

  int i, j, n, temp;

  int a[20];

  printf ("Enter the size of array\n");

  scanf ("%d", &n);

  printf ("Enter the elements of an array\n");

  for (i = 0; i < n; i++)

    {

      scanf ("%d", &a[i]);

    }

  printf (" the elements of an array before sorting are:\n");

  for (i = 0; i < n; i++)

    {

      printf ("%d\t", a[i]);

    }

  for (i = 0; i <= n - 1; i++)

    {

      for (j = 0; j < n - 1; j++)

{

  if (a[j] > a[j + 1])

    {

      temp = a[j];

      a[j] = a[j + 1];

      a[j + 1] = temp;

    }

}

    }

  printf ("the elements of an array after sorting are:\n");

  for (i = 0; i < n; i++)

    {

      printf ("%d", a[i]);

    }

}

why you using scanf

you want print element use printf

scanf for input value for user.