Conditionals aren't working.

Question

So... I'm doing a chatbot for fun and every sentence i write it returns the first conditional. I've tried:

 - Convert conditionals to variables.

 - Use text.find(text)

 - Use different compilers:

      · Python.org: the same

      · w3schools: no EOL allowed

Thank you in advance! (Code below)

import math
import random
import time

while True:
    text = input().lower().split()
    if "hello" or "hi" or "greetings" in text:
        print('Hello! I\'m PyChat, an artificial intelligence. How may I help you? ')
    elif "enjoy" or "like" or "fun" or "enjoys" or "likes" in text:
        print('I also enjoy that, what a coincidence!')

Answer 1

The problem is that your expression is evaluated like this:

if ("hello") or ("hi") or ("greetings" in text")

A string literal is always true, hence your program always prints "Hello..."

Instead, you could create a set of the keywords from the input and compare it to a set that contains the greetings. If these sets have an intersection (i.e. they are not disjoint), only then you print your message.

The code would be something like this:

greetings =  { "hi", "hello", "greetings" }
interests = { "enjoy", "enjoys", "like", "likes", "fun" }

while True:
    keywords = set(input().lower().split())
    if not keywords.isdisjoint(greetings):
        print('Hello! I\'m PyChat, an artificial intelligence. How may I help you?')
    elif not keywords.isdisjoint(interests):
        print('I also enjoy that, what a coincidence!')

Comments

Thank you! SOLVED

Answer 2

Hi! I tried to fix your problem. Here you go:

https://onlinegdb.com/iDPwY_Op3

Answer 3

The short answer is that order of operations is killing you.

6. Expressions — Python 3.11.2 documentation

 If you are not sure what order python is acting on your conditional specify.

Let me know if you need a sample..