why is this program not workig

Question

#include<stdio.h>
int main ()
  {
      int a,b,c,d,e,f,g,h,i,j,k,l,m;
    printf("enter 12 values");
    scanf("%d %d %d %d %d %d %d %d %d %d %d %d",&a,&b,&c,&d,&e,&f,&g,&h,&i,&j,&k,&l);
    m=a*b*c*d*e*f*g*h*i*j*k*l;
    printf("the mul of %d and %d and %d and %d and %d and %d and %d and %d and %d and %d and %d and %d is %d"a,b,c,d,e,f,g,h,i,j,k,l,m);
    return 99;
  }

Answer 1

#include<stdio.h>
int main ()
  {
      int a,b,c,d,e,f,g,h,i,j,k,l,m;
    printf("enter 12 values");
    scanf("%d %d %d %d %d %d %d %d %d %d %d %d",&a,&b,&c,&d,&e,&f,&g,&h,&i,&j,&k,&l);
    m=a*b*c*d*e*f*g*h*i*j*k*l;
    printf("after multipliction:%d",m);
    return 0;
  } you go with this code

Answer 2

comma (,) is missing after the " in 3rd from last line

Answer 3

You have an error in the following line of code

printf("the mul of %d and %d and %d and %d and %d and %d and %d and %d and %d and %d and %d and %d is %d"a,b,c,d,e,f,g,h,i,j,k,l,m);

you must put comma ',' to separate the print statement and the variables

edit : printf("the mul of %d and %d and %d and %d and %d and %d and %d and %d and %d and %d and %d and %d is %d",a,b,c,d,e,f,g,h,i,j,k,l,m);

Answer 4

because in 9th line ,in printf use comma before a u will no errors and u will answer 

#include<stdio.h>
int main ()
  {
      int a,b,c,d,e,f,g,h,i,j,k,l,m;

    printf("enter 12 values");
    scanf("%d %d %d %d %d %d %d %d %d %d %d %d",&a,&b,&c,&d,&e,&f,&g,&h,&i,&j,&k,&l);
    m=a*b*c*d*e*f*g*h*i*j*k*l;
    printf("the mul of %d and %d and %d and %d and %d and %d and %d and %d and %d and %d and %d and %d is %d",a,b,c,d,e,f,g,h,i,j,k,l,m);
    return 99;
  }

Answer 5

put , before a in 10th line 

Answer 6

%d"a, b... Wrong
%d",a, b... Right