help me to divide first number with last number ,second no with n-1,so on the result must be stored in an array

Question

#include<stdio.h>

void main()

{

int n,i,j,k,a[25],b[24];

printf("enter the number");

scanf("%d",&n);

printf("enter the array elements");

for(i=0;i<n;i++)

{

scanf("%d",&a[i]);

}

while(i<n,j<=0)

{

i=0;

j=n-1;

if(a[i]<a[j])

{

b[k]=a[j]%a[i];

printf("%d",b[k]);

k++;

}

else

{

b[k]=a[i]%a[j];

printf("%d",b[k]);

k++;

}

i++;

j--;

}

}

Answer 1

#include <stdio.h>

int

main ()

{

  char na[99], d, pj, pxy;

  int i;

  printf ("j2ll llmlj2 l

5kj9?(Y/N)\n");

  scanf ("%s", &d);

  if (d == 'Y' || d == 'y')

    {

      printf

("l4k&l lk %m4 l#<l8l.(l5k 20l, lk,8 lk %)\n");

      scanf ("%s", &na);

      printf ("l1k3l lk %m4 l#<l8l.(k(:M/l,:W)\n");

      scanf ("%s", &pxy);

      for (i = 0; i <= i + 1; i++)

{

  if (pxy == "M" || pxy == "W")

    {

      break;

    }

  else if (pxy == "M" || pxy == "W")

    {

    }

}

      printf

("l'll l mm4l#<l8l.\nl l,/k'k2l,/kl /j6l/l1l'l\n");

      scanf ("%d", &d);

      if (d == "l l,")

pj = 'l l,', printf ("%s(l<)k! l l'ml(l

5kk$!", pj);

    }

  else if (d == 'N' || d == 'n')

    printf ("j2ll l"k#m)kk$.");

  else

    printf ("\'Y\', \'N\'l<k! lk %m4 l#<l8l.");

  return 0;

}

HELP ME!!