I can run this but I think there is still smth wrong here, help pls

Question

#include <bits/stdc++.h>
using namespace std;

int main() {
   char n;
   cin >> n;
   if(n % 2 == 0){
   cout << "CHAN" ;
}
   else
{
   cout << "LE" ;
}

}

Answer 1

#include <bits/stdc++.h>
using namespace std;

int main() {
    char n;
    cin >> n;
    int num = n - '0'; // Convert char to int
    // Now we can use the modulus operator on the integer value
    if(num % 2 == 0){
        cout << "CHAN";
    } else {
        cout << "LE";
    }
}

Converting Character to Integer: in the below code snippet, it asks us to give input a [char]. Therefore, simply after that specific character is used in the modulus operation. Because only the modulus operator can run over an integer, it first needs to be converted from a character by changing each element in our digit list into its respective integer value. Int by num = n - '0'; Perform Modulus Operation: Once we have got the integer value of character, perform modulus operation and extract that element which will tell you number is odd or even.

Comments

hi can we use iostream too ??

Answer 2

changing the input form char to int will resolve your problem. as we are doing % operation it will be good if we use integer input than string.


#include <bits/stdc++.h>
using namespace std;

int main() {
   int n;
   cin >> n;
   if(n % 2 == 0){
   cout << "CHAN" ;
}
   else
{
   cout << "LE" ;
}

}