Passing command-line argument of int type always results in 2

Question

Hey! I'm new to OnlineGDB, I'm more accustomed to local IDEs. When I run this code:

#include <stdio.h>

void main(int n) {
    printf("%d", n);
}

with any integer in the "Command line arguments:" box, I get 2 as an output in the console. No matter what the integer is. I've even tried reloading the project. Nothing. Any ideas as to why this might be?

Answer 1

Your main function has the wrong signature. It should receive 2 parameters: argc and argv. The first is the number of arguments passed in from the operating system (including the 1st one, which is the location of the executable) and the 2nd is the array of arguments as strings (const char *).

See the below example:

#include <stdio.h>

int main(int argc, const char * argv[])
{
    printf("I've received %d number of arguments.\n", argc);
    for (int i = 0; i < argc; i++)
    {
        printf("\t%i. argument: %s\n", i, argv[i]);
    }

    return 0;
}

If you want to convert a string to a numeric type, you can use various functions, such as atoi().