Help me to Convert the following program using function

Question

include<stdio.h>

int main()

{

int arr[5],i,item;

printf("enter any five element=\n");

for(i=0;i<5;i++)

{

scanf("%d",&arr[i]);

}

printf("enter the item to be searched=");

scanf("%d",&item);

for(i=0;i<5;i++)

{

if(arr[i]==item)

{

printf("%d is found in the series",item);

break;

}}

if(i==5)

{

printf("%d is not found in the series",item);

}

return 0;

}

Answer 1

#include <stdio.h>

int search(int *arr, int size,int item)

{

    int i, loc=0;

    for (i = 0; i < size; i++)

    {

        if (arr[i] == item)

        {

            loc = i + 1;

        }

    }

    return loc;

}

void main(){

    int arr[100],item, size, i,location;

    printf("Enter the size of the array:");

    scanf("%d", &size);

    printf("Enter the elements of the array:");

    for (i=0; i<=size-1; i++)

    {scanf("%d", &arr[i]);}

    printf("Enter the element to be search:");

    scanf("%d", &item);

    location = search(arr, size,item);

    if(location == 0)

        {

            printf("Element not found.");

        } else{

            printf("Element found  at location %d.", location);

        }

}

Comments

This is a very unusual implementation. Normally, you return the element's index in the array, not index + 1.
If the element is not found a negative number (typically -1) is returned, not 0.

Answer 2

# include<stdio.h>
int search(int a[], int x);

int main()

{ int arr[5],i,item, found=0;
  printf("enter any five element=\n");
  for(i=0;i<5;i++)
  {   scanf("%d",&arr[i]);  }
  
  printf("enter the item to be searched="); scanf("%d",&item);
   
  found= search(arr,item);
  if (found==1) printf ("\n found") ; else printf("\nnot found");
  
}// end of main

int search(int a[], int x)
{ int i,ans=0;
  for(i=0;i<5;i++)
  { if(a[i]==x)
    {  printf("%d in function is found in the series",x);ans=1;
      break;}
  }
 
  if(i==5)
  { ans=0; printf("%d in function is not found in the series",x);}
       
   return(ans);
}

Comments

This does not work right. If the element is found, search() always returns 1, although it normally should return the index of the element.

Furthermore, the search() function knows about the length of the passed-in array, which makes this function very specific and would not work with any other arrays with different lengths. The usual solution is to pass in the length of the array as well.

Answer 3

https://question.onlinegdb.com/16684/write-the-following-program has an example of how to use functions.

Answer 4

This is how your going to change your code to the functions

#include<stdio.h>

int arr[5],i,item;

void enterelements()

{

printf("enter any five element=\n");

for(i=0; i<5; i++)

{

scanf("%d",&arr[i]);

}

}

void searchelements() {

printf("enter the item to be searched=");

scanf("%d",&item);

for(i=0; i<5; i++)

{

if(arr[i]==item)

{

printf("%d is found in the series",item);

break;

}

}

if(i==5)

{

printf("%d is not found in the series",item);

}

}

int main()

{

    enterelements(arr[5],i);

    searchelements(item,i,arr[5]);

return 0;

}

Comments

enterelements(arr[5],i);
searchelements(item,i,arr[5]);

your functions take no parameters, so you shouldn't provide any arguments. Especially wrong ones.

Answer 5

#include <stdio.h>

void search(int arr[],int ser[],int s,int t){

    for(int i=0;i<s;i++){

        if(arr[i]==t)ser[i]=1;

        else ser[i]=0;

    }

    return;

}

 int main(){

    int s;

    printf("Enter size of array: ");

    scanf("%d", &s);

   

    int arr[s];  

    printf("Enter elements : ");

    for (int i = 0; i < s; i++) {

        scanf("%d", &arr[i]);  

    }

   

    int t;

    printf("Enter target element to search: ");

    scanf("%d", &t);

    int ser[s];

    search(arr,ser,s,t);

    printf("Elements with same target value : ");

    int sum=0;

    for(int i=0;i<s;i++){

        sum+=ser[i];

    if(ser[i]==1){printf(" %d",i+1);}

    }

    if(sum==0){printf("Not Found");}

    return 0;

 }