Question

a c program to convert decimal to binary

Answer 1

#include<iostream.h>
#include<stdio.h>
#include<conio.h>
void main()
{
long a[500],i,j=0,c;
float m=0;
int n,b[30];
char s;
clrscr();

up:cout<<"Enter number"<<endl;
scanf("%d.%f",&n,&m);

for(i=0;n>0;i++)
{
a[i]=n%2;
n=n/2;
j++;

}
i=0;
while(m>1)
{m=m/10;
cout<<"m="<<m<<endl;
i++;

}
cout<<endl<<"i="<<i<<endl;
c=i;

for(i=i;i>=1;i--)
{m=m*2.0;
  if(m>1)
{b[i]=1;
m=m-1;
}
else
{
b[i]=0;
}
cout<<"m="<<m<<endl<<"b["<<i<<"]="<<b[i]<<endl;
}

cout<<"Binary equivalent is:"<<endl;
while(j>0)
{
cout<<a[j-1];
j--;
}
 cout<<".";
for(i=c;i>=1;i--)
{ cout<<b[i];
}

cout<<endl<<"Do you want to convert next number?"<<endl<<"If yes press y if not press n"<<endl;
cin>>s;
if(s=='y'||s=='Y')
{goto up;
}
else
{
cout<<"Thank You!";
}

getch();
}

Answer 2

#include<stdio.h>

#include<stdlib.h>

int main(int argc, char *argv[])

{

int x,r,i=0,j,q,s[10];

if(argc<2)

{

printf("please enter a number greater than zero\n");

exit(1);

}

x=atoi(argv[1]);

while(x>0)

{

s[i]=x%2;

x=x/2;

i++;

}

for(j=i-1;j>=0;j--)

{

printf("%d",s[j]);

}

}

Answer 3

#include <stdio.h>
#include <stdlib.h>
#include <assert.h>

int calcul( int val)
{
    int tmp;    //temporary binary number
    long int res;
    int start; //number used in the loop
    int power; //2*2*2 etc
    
    start = val;
    res = 0; //resultat binaire
    
    while(1)
    {
        tmp = 1;
        power = 1;
        while( (power * 2) <= start )
        {
            power = power * 2; //memorization of the value
            tmp *= 10; //we move the temporary number on the left
        }
        //add the new value to the old one
        res += tmp;
        
        //new number to determine
        start -= power;
        
        if( !start )
        {
            //that's the end
            break;
        }
        
    }
    
    return res;
}

int main()
{
    int val;
    int res;
    
    while (1)
    {
        printf( "enter the numer to convert or 0 to stop : ");
        scanf( "%d", &val );
        if( !val )
        {
            return 0;
        }
        //binary calculation
        res = calcul( val);
        printf( "binary (%d)\n", res );
        
    }

    return 0;
}

Answer 4

#include<stdio.h>

int main()

{

int a,nu,b[100];

scanf("%d",&n);

while(n!=0)

a[i]=n%2;

n=n/2;

i++;

while(i--)

printf("%d",a[i]);

}

Answer 5

#include <stdio.h>

#include <math.h>

int main()

{

int x, teste;

scanf("%d", &x);

teste = pow(2,lenN(x));

while(teste>0)

{

if(x & teste)

{

printf("1");

}

else

{

printf("0");

}

teste=teste/2;

}

return 0;

}

int lenN(int x)

{

int cont=0;

while(x!=1)

{

x=x/2;

cont++;

}

return cont;

}