Scope defines where variables can be accessed. What variables are within the scope of the inner2 function?

Question

 
 def outer1(i):
  j = i + 1
  def outer2():
    k = j + 1
    def inner1():
      m = k + 1
      def inner2():
        n = m + 1
        return n
      m = inner2()
      return m
    k = inner1()
    return k
  j = outer2()
  return j
  
print ("outer1(1) = ", outer1(1))

Answer 1

A pretty useful reading material on scopes in Python: https://www.w3schools.com/python/python_scope.asp

Not counting global and nonlocal variables (you do not have any of these by the way), in inner2 the following variables are visible:

def outer1(i):
  j = i + 1
  def outer2():
    k = j + 1
    def inner1():
      m = k + 1
      def inner2():
        n = m + 1
        return n
      m = inner2()
      return m
    k = inner1()
    return k
  j = outer2()
  return j
  
print ("outer1(1) = ", outer1(1))

That is, all the variables (i, j, k, m, n) is visible in inner2. See the "Function Inside Function" section in the above link.