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Finding repeated integers and their frequency.

0 votes
asked Aug 28, 2018 by Novice (240 points)
edited Aug 29, 2018 by Novice
Hello, I am a Novice.

I wanted to find the unique integers, repeated integers, and their frequency. Here I'm using 10 integers. This is my code for now. Can you explain to me where I am wrong and how should I fix it? Also How show to display unique integers.

#include <stdio.h>

int main()

{

int i , j, repeated , number[10]={1,2,2,1,3,5,3,7,9,1};

      printf("Enter 10 integers :");

for(i=0; i<10; i++)

{

repeated = 0;

    for(j=0; j<10; j++)

    {

       if(number[i]==number[j])

       {

        repeated++;

        }

    }

      printf("\n%d was repeated %d times\n",number[i],repeated);

}

return 0;

}

2 Answers

0 votes
answered Aug 28, 2018 by kanth (200 points)
you have to print "repeated" in the last print statement instead of c which is undecleared
commented Aug 29, 2018 by Novice (240 points)
that really wasn't the problem. I was changing the variable from 'c' to 'repeated' that is when I missed it. But it was when I copied it here. Thanks for pointing it out though.
0 votes
answered Sep 4, 2018 by anonymous

ok, I don't know what exactly you want the output to look like, but I can see that

in you'r code there's a needless repetition, for example, you count that number '1' is repeated 3 times

 3 different times!, so what I suggest to you to indicate the a certain number is checked, for Example, when you checked

for number 1 remove it from the array!, what do I mean by remove, if you have for example a postiive array you can put '-1'

to mark that an element is removed from here and skip, so you don't count the repition of number '1' many times.

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