Question

how can i write code for square roots of a number

Answer 1

It is as simple as raising the number to the power of half. For example in python, you could:

num_squared = num ** 0.5

Answer 2

Most languages have libraries that offer such functionality.

What language are you looking for?

Writing a function that calculates the square root without using library functions is a different kind of beast. :)

Answer 3

depends on the language, but in python you can use sqrt() to achieve this.

Answer 4

#include <iostream>
#include <cmath>
using namespace std;

int main()
{
    double number = 49;

    cout << sqrt(number) << endl;

    return 0;
}

Answer 5

Newton-Raphson Method 

#include <stdio.h>
#include <math.h>

// Newton-Raphson sqrt implementation
double sqrt_newton(double x, double tolerance, int maxIter) {
    if (x < 0) return NAN; // Handle negative input
    if (x == 0 || x == 1) return x; // Edge cases
    
    double y = x / 2.0; // Initial guess
    
    for (int i = 0; i < maxIter; i++) {
        double y_new = (y + x / y) / 2;
        
        if (fabs(y_new - y) < tolerance || fabs(y_new * y_new - x) < tolerance) {
            return y_new;
        }
        
        y = y_new;
    }
    
    return y;
}

// Test function
int main() {
    double test_values[] = {0, 1, 2, 4, 9, 16, 25, 100, 0.25, 0.5};
    int num_tests = sizeof(test_values) / sizeof(test_values[0]);
    
    printf("Testing sqrt_newton implementation:\n");
    printf("Value\t\tNewton\t\tMath sqrt\t\tDifference\n");
    printf("--------------------------------------------------------\n");
    
    for (int i = 0; i < num_tests; i++) {
        double x = test_values[i];
        double newton_result = sqrt_newton(x, 1e-10, 100);
        double math_result = sqrt(x);
        double diff = fabs(newton_result - math_result);
        
        printf("%.6f\t\t%.10f\t\t%.10f\t\t%.2e\n", 
              x, newton_result, math_result, diff);
    }
    
    return 0;
}

Answer 6

import math

num = float(input("Enter a number: "))
result = math.sqrt(num)

print("Square root =", result)

Answer 7

for C

#include <math.h>

int main(){

int num = 4, res;

res = sqrt(num);

printf("%d", res);

}