Program to count punctuation marks in the string using methods

Question

We have to use only methods and string

Answer 1

FOR 'C'

 

#include <stdio.h>
#include <stdlib.h>
void main(){
    int n,i=0,j,p=0;
    char punctuation[] = {'!', '"', '#', '$', '%', '&','(', ')', '*', '+', ',', '-','.', '/', ':', ';', '<', '=','>', '?', '@', '[', '\\', ']','^', '_', '`', '{', '|', '}', '~'};
    printf("Enter the lenght of string you want to enter : ");
    scanf("%d",&n);
    getchar();
    n++;
    char *s=(char*)malloc(n*sizeof(char));
    printf("Enter the string : ");
    fgets(s,n,stdin);
    while (s[i]!='\0'){
        for (j=0;j<31;j++){
            if (s[i]==punctuation[j]){
                p++;
            }
        }
        i++;
    }
    printf("-------------------------------------------------------------------------------------------------------------------------------------");
    printf("\nThere are total %d punctuation marks in the string you entered",p);
    printf("\n-------------------------------------------------------------------------------------------------------------------------------------");
}

FOR 'PYTHON'

punctuation = ['!', '"', '#', '$', '%', '&', "'",'(', ')', '*', '+', ',', '-','.', '/', ':', ';', '<', '=','>', '?', '@', '[', '\\', ']','^', '_', '`', '{', '|', '}', '~']
a=input("Enter the string : ")
p=0
for i in range(len(a)):
    for j in range(len(punctuation)):
        if a[i]==punctuation[j]:
            p+=1
print("-------------------------------------------------------------------------------------------------------------------------------------")
print("There are",p,"punctuation marks in the string")
print("-------------------------------------------------------------------------------------------------------------------------------------")