Question

code to print 1 1 1 1 in 1st row,1 0 0 1 in 2nd row, 1 0 0 1 in 3rd row, 1 1 1 1 in 4th row

Answer 1

print("1111/

1001/

1111")

Answer 2

#include<stdio.h>

int main()

{

  int i, j;

for(i=1; i<=4; i=i++)

{

 for(j=1; j<=4; j=j++)

{

   if(j=4 || j=1|| i=1 || i=4)

printf("1");

else

printf("0")

}

printf("\n");

}

return o;

}

Answer 3

#include<stdio.h>

int main()

{

  int i, j,r,c;

scanf("%d",&r);

scanf("%d",&c);

for(i=1; i<=r; i++)

{

 for(j=1; j<=c; j++)

{

   if(j==1||j==r||i==1||i==c)
   {

printf("1");
}
else

printf("0");

}

printf("\n");

}
}

Answer 4

for i in range(1,4):
    for j in range(1,4):
        if i==1 or i==4 or j==1 or j==i:
            print ('1');
        else:
            print('0')

Answer 5

public class Main

{

public static void main(String[] args) {

int i,j;

for (i=0;i<4;i++)

{   

    for(j=0;j<4;j++)

    {

        if( j==0 | j==3 | i==0 | i== 3)

        {

            System.out.print("1 ");

        }

        else

        {

            System.out.print("0 ");

        }

    }

         System.out.println("");

}

}

}

Answer 6

#include <stdio.h>

int main()

{

int i,j;

i=1;

for(i==1,j<=1,j++);

printf("%d",i);

return 0:

}

Answer 7

#include<stdio.h>

void main()

{

printf("\n 1 1 1 1 \n 1 0 0 1 \n 1 0 0 1 \n 1 1 1 1");

}