I am getting no errors but no out put for my program??

Question

#include <iostream>

using namespace std;

int
main ()
{
  int x, a, b, sum, diff, product, divison;
  cout << "enter a no.\n";
  cin >> a;
  cout << "enter another no. \n";
  cin >> b;
  cout << "enter the operator\n";
  cin >> x;

  if (x == sum)
    {
      sum = a + b;
      cout << "sum=" << sum << endl;
    }
  else if (x == diff)
    {
      diff = a - b;
      cout << "diff=" << diff << endl;

    }
  else if (x == product)
    {
      product = a * b;
      cout << "product=" << product << endl;

    }
  else if (x == divison)
    {
      divison = a / b;
      cout << "divison=" << divison << endl;
    }
  return 0;
}

when I ran this program online it gave the accurate result.... but when I tried running this program on my computer I get no output just three entries but no result

Answer 1

change the sum,diff,product,division with the number because the x is an integer variable it cannot store alphabets

Answer 2

You have

int x, a, b, sum, diff, product, divison;

and then you use sum, diff, product, and divison without giving those variables a value;

It is undefined behaviour to use variables that you haven't given a value.  I would change that line to:

int x, a, b, sum = 1, diff = 2, product = 3, divison = 4;

Then when the program asks for the operator you can use 1, 2, 3 or 4 for the operator to get sum, difference, multiplication or division.

You could always change the program like this:

int a, b;

char x, sum = '+', diff = '-', product = '*', divison = '/';

And then when the program asks for the operator you can use +, -, * or / for the operator to get sum, difference, multiplication or division.  You will have to change the variables used to store the answer to something that isn't a char so instead of storing it in the sum, diff, product and division variables you could store it in a variable called 'answer'.

Keep in mind that the way you are doing division is integer division.  You need to make the answer variable a double and do the division by casting a or b to a double before doing the division