# How can I put a 0 in that location of the arrangement (C++)?

+1 vote
asked Mar 8, 2020

I have to make an arrangement (array) were, when the number given by the person is even, it displays something like this:

Example: N=6

1 1 1 1 1 1

1 0 0 0 0 1

1 0 0 0 0 1

1 0 0 0 0 1

1 0 0 0 0 1

1 1 1 1 1 1

And when the number is odd it is something like this (with the 0 in the center):

Example: N=7

0 0 0 0 0 0 0

0 1 1 1 1 1 0

0 1 1 1 1 1 0

0 1 1 0 1 1 0

0 1 1 1 1 1 0

0 1 1 1 1 1 0

0 0 0 0 0 0 0

I have everything already, except the 0 in the center part... which I don't really know how to put. Can anybody help me please? This is what I got:

*******************************************************************************

#include <iostream>

using namespace std;

int main()

{

int ren, col, n, res=0;

cout<<"Give me a number: ";

cin>>n;

int arreglo[n][n];

res=n%2;

for (ren=0; ren<n; ren++)

{

for (col=0; col<n; col++)

{

if (res==0)

{

if (ren==0 || col==0 || ren==n-1 || col==n-1)

arreglo[ren][col]=1;

else

arreglo[ren][col]=0;

cout<<arreglo[ren][col]<<"  ";

}

else

{

if (ren==0 || col==0 || ren==n-1 || col==n-1)

arreglo[ren][col]=0;

else

arreglo[ren][col]=1;

cout<<arreglo[ren][col]<<"  ";

}

}

cout<<"-"<<endl;

}

return 0;

}

## 1 Answer

0 votes
answered Mar 9, 2020 by FreeKill
#include <iostream>
#include <cstdlib>

using namespace std;

int main()

{

int ren, col, n, res=0;

cout<<"Give me a number: ";

cin>>n;

int arreglo[n][n];

res=n%2;

for (ren=0; ren<n; ren++)

{

for (col=0; col<n; col++)

{

if (res==0)

{

if (ren==0 || col==0 || ren==n-1 || col==n-1)

arreglo[ren][col]=1;

else

arreglo[ren][col]=0;

cout<<arreglo[ren][col]<<"  ";

}

else

{

if (ren==0 || col==0 || ren==n-1 || col==n-1)

arreglo[ren][col]=0;

else if((ren==div(n,2).quot)&&(col==div(n,2).quot))

arreglo[ren][col]=0;

else

arreglo[ren][col]=1;

cout<<arreglo[ren][col]<<"  ";

}

}

cout<<"-"<<endl;

}

return 0;

}