Question

algorithm of palindrome

Answer 1

//Hi, this is c++

#include <iostream>

using namespace std;
long u, n, r, aux;
int main()
{
    cin>>n;
    aux=n;
    r=0;
    do{
        u=aux%10;
        r=r*10+u;
    }while(aux>0);
    if(n==r){
        cout<<"palindrom"<<endl;
    }
    else
     cout<<"no palindrom";

    return 0;
}

Comments

is it correct?

Answer 2

//Hi, this is c++

#include <iostream>

using namespace std;
long u, n, r, aux;
int main()
{
    cin>>n;
    aux=n;
    r=0;
    do{
        u=aux%10;
        r=r*10+u;
    }while(aux>0);
    if(n==r){
        cout<<"palindrom"<<endl;
    }
    else
     cout<<"no palidrom";

    return 0;
}

Answer 3

cout << "Is your number a palindrome? " << endl;
    cout << "---------------------------- " << endl;
    
    /// INPUT
        number = -1;
        cout << "Input a positive number: ";
        cin >> number;
        cout << "number= " << number << endl;

    
    if(number <= 0)
    {
        cout << "not allowed" << endl;
        return 1;
    }

    /// CALCULATION
    for ( input = number ; input > 0 ; input /= 10)  // cut the last digit from input from right (last out)
    {
        output=output*10 + input%10;                 // shift output one digit left and put that cutted digit in (first in)
        
        cout << "input=" << input <<  " output=" << output << endl;  //
    }
    
    /// OUTPUT
    if(output == number)
    {
        cout<<"palindrom";
    }
    else
    {
        cout<<"no palindrom";
    }